(2) \( \left(7 \cdot \frac{1}{7}\right) \cdot\left(\frac{3}{2}\right)-3 \frac{1}{2} \)

Let's simplify the expression step-by-step. First, calculate \( 7 \cdot \frac{1}{7} \): \[ 7 \cdot \frac{1}{7} = 1 \] Now substitute this back into the expression: \[ 1 \cdot \left(\frac{3}{2}\right) - 3 \frac{1}{2} \] Since \( 1 \cdot \frac{3}{2} = \frac{3}{2} \), we can rewrite the expression as: \[ \frac{3}{2} - 3 \frac{1}{2} \] Next, convert \( 3 \frac{1}{2} \) into an improper fraction: \[ 3 \frac{1}{2} = 3 + \frac{1}{2} = \frac{6}{2} + \frac{1}{2} = \frac{7}{2} \] Now substituting this into the expression gives us: \[ \frac{3}{2} - \frac{7}{2} = \frac{3 - 7}{2} = \frac{-4}{2} = -2 \] So, the result of the expression \( \left(7 \cdot \frac{1}{7}\right) \cdot\left(\frac{3}{2}\right)-3 \frac{1}{2} \) is: \[ \boxed{-2} \]