$$ P ( - 0.23

Question

$$ P ( - 0.23 < z < 2.30 ) = \square 	imes 5 $$

UpStudy AI · Accepted Answer

We are given a standard‐normal probability:

$$
P(-0.23 < z < 2.30)=\Phi(2.30)-\Phi(-0.23)
$$

1. First, look up (or use a calculator for) the cumulative probability for $$ z = 2.30 $$. Standard normal tables give:

$$
\Phi(2.30) \approx 0.9893
$$

2. Next, use the symmetry of the normal distribution to compute:

$$
\Phi(-0.23)=1-\Phi(0.23)
$$

A table gives:

$$
\Phi(0.23) \approx 0.5910
$$

So,

$$
\Phi(-0.23) \approx 1-0.5910=0.4090
$$

3. Now, calculate the probability:

\[
P(-0.23The probability $$ P(-0.23 < z < 2.30) $$ is approximately $$ 0.1161 \times 5 $$.

Upstudy AI Solution