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Factor. \( -3 v^{2}-17 v+56 \) Select the correct choice below and, if necessary, fill in the answer box to complete your choice. A. \( -3 v^{2}-17 v+56=\square \) (Factor completely.) B. The trinomial is not factorable.

Ask by Robbins Newton. in the United States
Feb 24,2025

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Tutor-Verified Answer

Answer

\( -3v^{2}-17v+56 = -(v+8)(3v-7) \)

Solution

Factor the expression \( -3v^{2}-17v+56 \). Factor the expression by following steps: - step0: Factor: \(-3v^{2}-17v+56\) - step1: Rewrite the expression: \(-3v^{2}+\left(7-24\right)v+56\) - step2: Calculate: \(-3v^{2}+7v-24v+56\) - step3: Rewrite the expression: \(-v\times 3v+v\times 7-8\times 3v+8\times 7\) - step4: Factor the expression: \(-v\left(3v-7\right)-8\left(3v-7\right)\) - step5: Factor the expression: \(\left(-v-8\right)\left(3v-7\right)\) - step6: Factor the expression: \(-\left(v+8\right)\left(3v-7\right)\) The expression \(-3v^{2}-17v+56\) can be factored as \(-(v+8)(3v-7)\). Therefore, the correct choice is: A. \(-3v^{2}-17v+56=-(v+8)(3v-7)\)

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To factor the expression \( -3 v^{2} - 17 v + 56 \), we begin by looking for two numbers that multiply to \( -3 \times 56 = -168 \) and add up to \( -17 \). The pair of numbers that meet these criteria is \( -21 \) and \( 8 \). Next, we can rewrite the trinomial using these numbers: \[ -3v^{2} - 21v + 8v + 56. \] Now, group the terms: \[ (-3v^{2} - 21v) + (8v + 56). \] Factoring out the common factors from each group results in: \[ -3v(v + 7) + 8(v + 7). \] Now we can factor out the common binomial factor: \[ (v + 7)(-3v + 8). \] So, the complete factorization is: \[ -3v^{2} - 17v + 56 = (v + 7)(-3v + 8). \] Thus, the correct choice is: A. \( -3 v^{2}-17 v+56=(v + 7)(-3v + 8). \) This means you can now confidently move on to tackle similar problems! Remember, factoring is all about finding patterns and common elements. When you're stuck, try rewriting or grouping – it can make all the difference!

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