Calculate the following and leave your answer in simplest fraction form: \( \begin{array}{lll}\text { (1) } 3 \frac{1}{2}+2 \frac{1}{3} & \text { (2) } 3 \frac{1}{4}-2 \frac{2}{3} & \text { (3) } 1 \frac{3}{4}+3 \frac{2}{3} \\ \text { (4) }-1 \frac{1}{5}+\frac{3}{4} & \text { (5) }-1 \frac{1}{2}-2 \frac{1}{4} & \text { (6) } 2 \frac{1}{10}-3 \frac{1}{5} \\ \text { (7) } 3 \frac{3}{4}-5 \frac{2}{3} & \text { (8) } 1 \frac{1}{3}+2 \frac{1}{2}+1 \frac{3}{4} & \text { (9) } 2 \frac{5}{8}+\frac{1}{3}+1 \frac{1}{12} \\ \text { (10) } 1 \frac{1}{4}-2 \frac{2}{5}-1 \frac{1}{5} & \text { (11) } 2 \frac{3}{4}-\left(\frac{1}{3}+\frac{1}{2}\right) & \text { (12) } 3 \frac{1}{2}-\left(1 \frac{1}{6}-2 \frac{1}{4}\right)\end{array} \)

Let's calculate each of these expressions one by one and simplify the answers to fraction form when necessary. 1. \(3 \frac{1}{2} + 2 \frac{1}{3} = \frac{7}{2} + \frac{7}{3} = \frac{21}{6} + \frac{14}{6} = \frac{35}{6} = 5 \frac{5}{6}\) 2. \(3 \frac{1}{4} - 2 \frac{2}{3} = \frac{13}{4} - \frac{8}{3} = \frac{39}{12} - \frac{32}{12} = \frac{7}{12}\) 3. \(1 \frac{3}{4} + 3 \frac{2}{3} = \frac{7}{4} + \frac{11}{3} = \frac{21}{12} + \frac{44}{12} = \frac{65}{12} = 5 \frac{5}{12}\) 4. \(-1 \frac{1}{5} + \frac{3}{4} = -\frac{6}{5} + \frac{3}{4} = -\frac{24}{20} + \frac{15}{20} = -\frac{9}{20}\) 5. \(-1 \frac{1}{2} - 2 \frac{1}{4} = -\frac{3}{2} - \frac{9}{4} = -\frac{6}{4} - \frac{9}{4} = -\frac{15}{4} = -3 \frac{3}{4}\) 6. \(2 \frac{1}{10} - 3 \frac{1}{5} = \frac{21}{10} - \frac{15}{10} = \frac{6}{10} = \frac{3}{5}\) 7. \(3 \frac{3}{4} - 5 \frac{2}{3} = \frac{15}{4} - \frac{17}{3} = \frac{45}{12} - \frac{68}{12} = -\frac{23}{12} = -1 \frac{11}{12}\) 8. \(1 \frac{1}{3} + 2 \frac{1}{2} + 1 \frac{3}{4} = \frac{4}{3} + \frac{5}{2} + \frac{7}{4} = \frac{16}{12} + \frac{30}{12} + \frac{21}{12} = \frac{67}{12} = 5 \frac{7}{12}\) 9. \(2 \frac{5}{8} + \frac{1}{3} + 1 \frac{1}{12} = \frac{21}{8} + \frac{4}{12} + \frac{13}{12} = \frac{21}{8} + \frac{17}{12}\) Common denominator: \(\frac{63}{24} + \frac{34}{24} = \frac{97}{24} = 4 \frac{1}{24}\) 10. \(1 \frac{1}{4} - 2 \frac{2}{5} - 1 \frac{1}{5} = \frac{5}{4} - \frac{12}{5} - \frac{6}{5} = \frac{5}{4} - \frac{18}{5}\) Common denominator: \(\frac{25}{20} - \frac{72}{20} = -\frac{47}{20} = -2 \frac{7}{20}\) 11. \(2 \frac{3}{4} - \left(\frac{1}{3} + \frac{1}{2}\right) = \frac{11}{4} - \left(\frac{5}{6}\right) = \frac{11}{4} - \frac{10}{12}\) Common denominator: \(\frac{33}{12} - \frac{10}{12} = \frac{23}{12} = 1 \frac{11}{12}\) 12. \(3 \frac{1}{2} - \left(1 \frac{1}{6} - 2 \frac{1}{4}\right) = \frac{7}{2} - \left(\frac{7}{6} - \frac{9}{4}\right)\) Common denominator for \(1 \frac{1}{6}\)