Solve the system of linear equations by substitution. \( \begin{array}{l}x=16-4 y \\ 3 x+4 y=8\end{array} \)

Solve the system of equations \( x=16-4y;3x+4y=8 \). Solve the system of equations by following steps: - step0: Solve using the substitution method: \(\left\{ \begin{array}{l}x=16-4y\\3x+4y=8\end{array}\right.\) - step1: Substitute the value of \(x:\) \(3\left(16-4y\right)+4y=8\) - step2: Simplify: \(48-8y=8\) - step3: Move the constant to the right side: \(-8y=8-48\) - step4: Subtract the numbers: \(-8y=-40\) - step5: Change the signs: \(8y=40\) - step6: Divide both sides: \(\frac{8y}{8}=\frac{40}{8}\) - step7: Divide the numbers: \(y=5\) - step8: Substitute the value of \(y:\) \(x=16-4\times 5\) - step9: Simplify: \(x=-4\) - step10: Calculate: \(\left\{ \begin{array}{l}x=-4\\y=5\end{array}\right.\) - step11: Check the solution: \(\left\{ \begin{array}{l}x=-4\\y=5\end{array}\right.\) - step12: Rewrite: \(\left(x,y\right) = \left(-4,5\right)\) The solution to the system of linear equations by substitution is \( x = -4 \) and \( y = 5 \).