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Compare and arrange the foll (a) \( -\frac{5}{6},-\frac{1}{4}, \frac{3}{8},-\frac{5}{12}, \frac{7}{24} \)

Ask by Robbins Rodriguez. in Malaysia
Mar 19,2025

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The numbers arranged from smallest to largest are: \[ -\frac{5}{6}, -\frac{5}{12}, -\frac{1}{4}, \frac{7}{24}, \frac{3}{8} \]

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To compare and arrange the numbers \( -\frac{5}{6}, -\frac{1}{4}, \frac{3}{8}, -\frac{5}{12}, \frac{7}{24} \), we can convert them all into a decimal form or a common denominator. 1. **Convert to decimal:** - \( -\frac{5}{6} \approx -0.8333 \) - \( -\frac{1}{4} = -0.25 \) - \( -\frac{5}{12} \approx -0.4167 \) - \( \frac{3}{8} = 0.375 \) - \( \frac{7}{24} \approx 0.2917 \) 2. **Arrange from least to greatest:** - \( -\frac{5}{6} \) - \( -\frac{5}{12} \) - \( -\frac{1}{4} \) - \( \frac{7}{24} \) - \( \frac{3}{8} \) So, the final arrangement is: \[ -\frac{5}{6}, -\frac{5}{12}, -\frac{1}{4}, \frac{7}{24}, \frac{3}{8} \]

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