Question
upstudy study bank question image url

Find value of \( X \) \( x^{X}=256 \)

Ask by Washington Norton. in Malaysia
Feb 28,2025

Upstudy AI Solution

Tutor-Verified Answer

Answer

To find the value of \( X \) in the equation \( x^{X} = 256 \), take the natural logarithm of both sides: \[ X = \frac{\ln(256)}{\ln(x)} \] This gives the general solution for \( X \) in terms of \( x \).

Solution

The equation is given by   x^X = 256. To solve for X in terms of x, we can use logarithms. Assuming x > 0 (with x ≠ 1), we take the natural logarithm of both sides:   ln(x^X) = ln(256). Using the logarithmic identity ln(a^b) = b · ln(a), we have:   X · ln(x) = ln(256). Now, solve for X:   X = ln(256) / ln(x). Thus, the solution is   X = (ln 256) / (ln x). Note that since 256 = 2^8, different choices for x will give specific numerical values for X. For example:  • If x = 2, then X = ln(256)/ln(2) = 8.  • If x = 4, then X = ln(256)/ln(4) = 4.  • If x = 16, then X = ln(256)/ln(16) = 2. Without additional information about x, the most general answer is X = (ln 256)/(ln x).

Answered by UpStudy AI and reviewed by a Professional Tutor

error msg
Explain
Simplify this solution

The Deep Dive

To solve the equation \( x^X = 256 \), we recognize that \( 256 \) can be expressed as a power of \( 2 \): \( 256 = 2^8 \). Thus, we can rewrite the equation as: \[ x^X = 2^8 \] Now, we can explore the possibilities for \( x \) and \( X \). If we set \( x = 2^k \) (where \( k \) is a positive integer), we can substitute into the equation: \[ (2^k)^X = 2^8 \] This simplifies to: \[ 2^{kX} = 2^8 \] From this point, we can equate the exponents: \[ kX = 8 \] Now we can find various pairs of \( (k, X) \) that satisfy this equation. For example, if \( k = 1 \), then \( X = 8 \); if \( k = 2 \), then \( X = 4 \); and if \( k = 4 \), then \( X = 2 \). Therefore, the equation \( x^X = 256 \) can have multiple solutions depending on the chosen values of \( x \) and \( X \). Ultimately, to find \( X \) uniquely, you'd need specific constraints or additional equations!

Related Questions

Try Premium now!
Try Premium and ask Thoth AI unlimited math questions now!
Maybe later Go Premium
Study can be a real struggle
Why not UpStudy it?
Select your plan below
Premium

You can enjoy

Start now
  • Step-by-step explanations
  • 24/7 expert live tutors
  • Unlimited number of questions
  • No interruptions
  • Full access to Answer and Solution
  • Full Access to PDF Chat, UpStudy Chat, Browsing Chat
Basic

Totally free but limited

  • Limited Solution
Welcome to UpStudy!
Please sign in to continue the Thoth AI Chat journey
Continue with Email
Or continue with
By clicking “Sign in”, you agree to our Terms of Use & Privacy Policy