Question
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t) \( \left(2^{3}+2^{4}\right)=2^{2}+\sqrt{9}-\sqrt{4} \)

Ask by Goodwin Martin. in Argentina
Mar 19,2025

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Tutor-Verified Answer

Answer

El lado izquierdo es 24 y el lado derecho es 5, por lo que la igualdad no es verdadera.

Solution

1. Evaluamos el lado izquierdo de la ecuación: \[ 2^3 + 2^4 = 8 + 16 = 24 \] 2. Evaluamos el lado derecho de la ecuación: \[ 2^2 + \sqrt{9} - \sqrt{4} = 4 + 3 - 2 = 5 \] 3. Comparamos ambos lados: \[ 24 \neq 5 \] Por lo tanto, la igualdad dada no es verdadera.

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To solve the equation \( \left(2^{3}+2^{4}\right)=2^{2}+\sqrt{9}-\sqrt{4} \), let’s break it down. On the left side, \( 2^3 = 8 \) and \( 2^4 = 16 \), so \( 2^3 + 2^4 = 8 + 16 = 24 \). On the right side, \( 2^2 = 4 \), \( \sqrt{9} = 3 \), and \( \sqrt{4} = 2 \). Therefore, \( 2^2 + \sqrt{9} - \sqrt{4} = 4 + 3 - 2 = 5 \). Now we have \( 24 = 5 \), which is not true. Hence, the equation is not valid. Isn't it interesting how things can sometimes look simple but reveal a hidden complexity? This example reminds us to check our calculations and assumptions carefully. You never know where the math will take you!

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