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\( \operatorname{Simpliyy}: \frac{\sqrt{9} \times 3^{4} \times 2^{5}}{\sqrt{16} \times(\sqrt{9})^{3}} \) \( = \) \( = \)

Ask by Carlson Wells. in South Africa
Mar 10,2025

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Tutor-Verified Answer

Answer

72

Solution

1. Replace the square roots with their numerical values: \[ \sqrt{9} = 3 \quad \text{and} \quad \sqrt{16} = 4. \] The expression becomes: \[ \frac{3 \times 3^4 \times 2^5}{4 \times 3^3}. \] 2. Combine the powers of \(3\) in the numerator: \[ 3 \times 3^4 = 3^{1+4} = 3^5. \] Now the expression is: \[ \frac{3^5 \times 2^5}{4 \times 3^3}. \] 3. Simplify the fraction by canceling the common factor \(3^3\): \[ \frac{3^5}{3^3} = 3^{5-3} = 3^2. \] Thus, the expression becomes: \[ \frac{3^2 \times 2^5}{4}. \] 4. Evaluate \(3^2\) and \(2^5\): \[ 3^2 = 9 \quad \text{and} \quad 2^5 = 32. \] So, the expression simplifies to: \[ \frac{9 \times 32}{4}. \] 5. Perform the multiplication and division: \[ 9 \times 32 = 288 \quad \text{and} \quad \frac{288}{4} = 72. \] The simplified result is: \[ 72. \]

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Simplify this solution

The Deep Dive

First, let's simplify each component step by step. The expression starts with the numerator: \( \sqrt{9} \times 3^{4} \times 2^{5} \). We know \( \sqrt{9} = 3 \), so that becomes \( 3 \times 3^{4} \times 2^{5} = 3^{1 + 4} \times 2^{5} = 3^{5} \times 2^{5} \). Now for the denominator: \( \sqrt{16} \times (\sqrt{9})^{3} \). Since \( \sqrt{16} = 4 \) and \( \sqrt{9} = 3\), we have \( 4 \times (3)^{3} = 4 \times 27 = 108 \). Therefore, the original expression simplifies to: \[ \frac{3^{5} \times 2^{5}}{108} \] Next, we simplify \( 108 \) which is \( 2^{2} \times 3^{3} \). So we can rewrite the entire expression as: \[ \frac{3^{5} \times 2^{5}}{2^{2} \times 3^{3}} \] Now simplifying gives us: \[ 3^{5-3} \times 2^{5-2} = 3^{2} \times 2^{3} = 9 \times 8 = 72 \] Thus, the simplified expression is \( 72 \).

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