\( \operatorname{Simpliyy}: \frac{\sqrt{9} \times 3^{4} \times 2^{5}}{\sqrt{16} \times(\sqrt{9})^{3}} \) \( = \) \( = \)
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The Deep Dive
First, let's simplify each component step by step. The expression starts with the numerator: \( \sqrt{9} \times 3^{4} \times 2^{5} \). We know \( \sqrt{9} = 3 \), so that becomes \( 3 \times 3^{4} \times 2^{5} = 3^{1 + 4} \times 2^{5} = 3^{5} \times 2^{5} \). Now for the denominator: \( \sqrt{16} \times (\sqrt{9})^{3} \). Since \( \sqrt{16} = 4 \) and \( \sqrt{9} = 3\), we have \( 4 \times (3)^{3} = 4 \times 27 = 108 \). Therefore, the original expression simplifies to: \[ \frac{3^{5} \times 2^{5}}{108} \] Next, we simplify \( 108 \) which is \( 2^{2} \times 3^{3} \). So we can rewrite the entire expression as: \[ \frac{3^{5} \times 2^{5}}{2^{2} \times 3^{3}} \] Now simplifying gives us: \[ 3^{5-3} \times 2^{5-2} = 3^{2} \times 2^{3} = 9 \times 8 = 72 \] Thus, the simplified expression is \( 72 \).