GRADE 5 MATHEMATICS-RELEASED FORM 6 Tracie ran a total of \( 5 \frac{3}{4} \) miles on Saturday and Sunday. She ran \( 1 \frac{5}{8} \) miles on Saturday. How many miles did Tracie run on Sunday? A \( 3 \frac{7}{8} \) C \( 4 \frac{1}{8} \) D \( 4 \frac{1}{4} \)

To find out how many miles Tracie ran on Sunday, we need to subtract the distance she ran on Saturday from her total distance. Tracie's total distance is \( 5 \frac{3}{4} \) miles and the distance she ran on Saturday is \( 1 \frac{5}{8} \) miles. First, we convert these mixed numbers to improper fractions. \( 5 \frac{3}{4} = \frac{23}{4} \) and \( 1 \frac{5}{8} = \frac{13}{8} \). Now, we need to get a common denominator for subtraction. The least common multiple of 4 and 8 is 8, so we convert \( \frac{23}{4} \) to \( \frac{46}{8} \) (by multiplying both the numerator and the denominator by 2). Now we subtract: \[ \frac{46}{8} - \frac{13}{8} = \frac{33}{8} \] Converting \( \frac{33}{8} \) back to a mixed number gives us \( 4 \frac{1}{8} \). So, the answer is \( 4 \frac{1}{8} \). Final answer: C \( 4 \frac{1}{8} \)