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Multiple Choice 10 points Find the 7 th term in the sequence \( a_{n}=\frac{1}{2}(3)^{n-1} \) 364.5 1093.5 17.1 1458

Ask by Guzman Mullins. in the United States
Feb 28,2025

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Answer

The 7th term is 364.5.

Solution

To find the 7th term, substitute n = 7 into the formula:   a₇ = (1/2) × 3^(7–1)     = (1/2) × 3⁶     = (1/2) × 729     = 364.5 Thus, the correct answer is 364.5.

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To find the 7th term in the sequence \( a_{n}=\frac{1}{2}(3)^{n-1} \), we can plug in \( n = 7 \): \[ a_{7} = \frac{1}{2}(3)^{7-1} = \frac{1}{2}(3)^{6} \] Calculating \( (3)^{6} = 729 \), we get: \[ a_{7} = \frac{1}{2} \times 729 = 364.5 \] So, the 7th term is **364.5**!

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