In each blank with an integer (signed number). \begin{tabular}{|l|}\hline (a) \( -3-(-5)=-3+\square \) \\ \hline (b) \( -4-1=-4+\square \) \\ \end{tabular}

1. For part (a): We have \[ -3 - (-5) = -3 + \square. \] Since subtracting a negative number is equivalent to adding the positive, \[ -3 - (-5) = -3 + 5. \] Thus, the blank should be filled with \(5\). 2. For part (b): We have \[ -4 - 1 = -4 + \square. \] Calculating the left side gives \[ -4 - 1 = -5. \] So, we need \[ -4 + \square = -5. \] To find the blank, add \(4\) to both sides: \[ \square = -5 + 4 = -1. \] The answers are: - (a) \(5\) - (b) \(-1\)