The approximate dimensions of a swimming pool are 160 ft by 82 ft by 6.3 ft .
a. Find the volume of the pool.
b. If gal, about how many gallons does the pool hold?
a. The volume of the pool is approximately .
(Round to the nearest integer as needed.)
b. The pool holds about gallons of water.
(Round to the nearest integer as needed.)

Ask by Greene Summers. in the United States

Mar 28,2025

Question

The approximate dimensions of a swimming pool are 160 ft by 82 ft by 6.3 ft .
a. Find the volume of the pool.
b. If gal, about how many gallons does the pool hold?
a. The volume of the pool is approximately .
(Round to the nearest integer as needed.)
b. The pool holds about gallons of water.
(Round to the nearest integer as needed.)

Ask by Greene Summers. in the United States

Mar 28,2025

UpStudy AI · Accepted Answer

**a. Find the volume of the pool**

The pool dimensions are given as:
- Length: $$160$$ ft
- Width: $$82$$ ft
- Depth: $$6.3$$ ft

The volume $$V$$ of a rectangular prism is calculated by:
$$
V = \text{length} \times \text{width} \times \text{depth}
$$

Substitute the given values:
$$
V = 160 \times 82 \times 6.3
$$

First, compute the product of the length and width:
$$
160 \times 82 = 13\,120
$$

Then, multiply by the depth:
$$
13\,120 \times 6.3 = 82\,656 \quad \text{cubic feet}
$$

---

**b. Convert the volume to gallons**

We are given that:
$$
1 \, \text{cu ft} \approx 7.48 \, \text{gal}
$$

Multiply the volume in cubic feet by the conversion factor:
$$
\text{Gallons} = 82\,656 \times 7.48
$$

Calculate the product:
$$
82\,656 \times 7.48 \approx 618\,267 \quad \text{gallons}
$$

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**Final Answers:**

a. $$82\,656$$ cu ft

b. $$618\,267$$ gallons
a. The pool's volume is approximately 82,656 cubic feet. b. The pool holds about 618,267 gallons of water.