Solve \( \frac{1}{2}+\frac{1}{2 x}=\frac{x^{2}-7 x+10}{4 x} \) by rewriting the equation as a proportion. Which proportion is equivalent to the original equation? \( \frac{x+2}{2 x}=\frac{x^{2}-7 x+10}{4 x} \) \( \frac{x-1}{2 x}=\frac{x^{2}-7 x+10}{4 x} \) \( \frac{x+1}{2 x}=\frac{x^{2}-7 x+10}{4 x} \)

To solve the equation \( \frac{1}{2}+\frac{1}{2 x}=\frac{x^{2}-7 x+10}{4 x} \) by rewriting it in proportion form, start by finding a common denominator for the left side. The common denominator for \( \frac{1}{2} \) and \( \frac{1}{2x} \) is \( 2x \). Rewriting the left side: \[ \frac{1}{2} = \frac{x}{2x} \quad \text{and} \quad \frac{1}{2x} = \frac{1}{2x} \] So we have: \[ \frac{x + 1}{2x} = \frac{x^2 - 7x + 10}{4x} \] By cross-multiplying, this gives the proportion: \[ 4(x + 1) = 2(x^2 - 7x + 10) \] Thus, the equivalent proportion to the original equation is \( \frac{x + 1}{2x} = \frac{x^2 - 7x + 10}{4x} \). So the correct answer is: \(\frac{x+1}{2 x}=\frac{x^{2}-7 x+10}{4 x}\).