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Encontrar el valar natural de las siggientes funciunes a) \( \operatorname{Sec} 25^{\circ}= \) b) \( \operatorname{Coc} 48^{\circ}= \) c) \( \operatorname{Cot} 85^{\circ} 16^{\prime} 14^{\prime \prime}= \)

Ask by Cruz Mcfarlane. in Mexico
Mar 19,2025

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a) \(\sec 25^\circ \approx 1.1036\) b) \(\csc 48^\circ \approx 1.345\) c) \(\cot (85^\circ 16'14'') \approx 0.0828\)

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Para calcular el valor natural de \( \operatorname{Sec} 25^{\circ} \), recuerda que \( \operatorname{Sec} \theta = \frac{1}{\cos \theta} \). Por lo tanto, \( \operatorname{Sec} 25^{\circ} \) equivale a \( \frac{1}{\cos 25^{\circ}} \approx 1.082 \). En cuanto a \( \operatorname{Coc} 48^{\circ} \), esto posiblemente se refiere a \( \cot 48^{\circ} \), que también es igual a \( \frac{1}{\tan 48^{\circ}} \). El valor aproximado para \( \cot 48^{\circ} \) es \( \approx 1.11 \). Finalmente, al obtener \( \operatorname{Cot} 85^{\circ} 16^{\prime} 14^{\prime \prime} \), conviene convertir los minutos y segundos a fracciones de grados. Así, se calcula usando \( \cot (85.2705^{\circ}) \approx 0.074 \).

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