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Solve the inequality. Write the solution set in interval notation if possible. \[ (4 d+5)^{2}>-6 \] The solution set is \( \square . \square \)

Ask by Watkins Hampton. in the United States
Mar 19,2025

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Answer

The solution set is all real numbers, written as \( (-\infty, \infty) \).

Solution

1. Recognize that for any real number \(d\), the expression \((4d+5)^2\) is a square, and thus it is always nonnegative: \[ (4d+5)^2 \geq 0. \] 2. Since \(0 > -6\), it follows that: \[ (4d+5)^2 \geq 0 > -6. \] This means that the inequality \((4d+5)^2 > -6\) holds true for all real values of \(d\). 3. Therefore, the solution set in interval notation is: \[ (-\infty, \infty). \]

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Let's first consider the inequality \((4d + 5)^{2} > -6\). Noticing that the left side is a square, it is always non-negative, meaning it can never be less than zero. Thus, \((4d + 5)^{2} \geq 0\) for all real numbers \(d\). Since \(-6\) is less than \(0\), the inequality \((4d + 5)^{2} > -6\) is true for every real number \(d\). The solution set is \((-∞, ∞)\).

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