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Time left 1:29:18 Question 1 Not yet answered Marked out of 8.00 P Flag question Solve for the following signals The FT of \( x(t)=2 \operatorname{sinc}(4 t) \) is: Choose... The FT of \( x(t)=2 \pi(2 t-2) \) is: Choose... The FT of \( x(t)=2 \wedge\left(\frac{t-3}{2}\right) \), where \( \wedge \) is the triangular function Choose... The FT Of \( x(t)=\pi\left(\frac{t}{2}\right) e^{-j 10 \pi t} \) Choose... Question 2 Not yet answered Marked out of 10.00 P Flag question Consider the following signal: \[ x(t)=4 \cos ^{2}(20 \pi t)+2 \sqrt{2} \sin \left(30 \pi t+\frac{\pi}{4}\right) \] The value of \( a_{1} \) is Choose... The dc-value of the signal \( x(t) \) is Choose... The average power is \( \square \) The value of \( X_{-4} \) is Choose... The fundamental Frequency \( f_{O} \) is Choose...

Ask by Matthews Higgins. in Israel
Jan 30,2025

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**Question 1:** 1. The Fourier Transform of \( x(t) = 2 \operatorname{sinc}(4t) \) is \( \frac{1}{2} \operatorname{rect}\left(\frac{f}{8}\right) \). 2. The Fourier Transform of \( x(t) = 2\pi(2t - 2) \) is \( 2\pi j \delta'(f) - 4\pi^2 \delta(f) \). 3. The Fourier Transform of \( x(t) = 2 \wedge\left(\frac{t-3}{2}\right) \) is \( 4 \operatorname{tri}(2f) e^{-j 3f} \). 4. The Fourier Transform of \( x(t) = \pi\left(\frac{t}{2}\right) e^{-j 10\pi t} \) is \( 2 \operatorname{rect}(f + 5) \). **Question 2:** 1. \( a_{1} = 0 \) 2. DC value = 2 3. Average power = 10 4. \( X_{-4} = 0 \) 5. Fundamental frequency \( f_{O} = 60 \) Hz

Solution

Let's solve the problems step by step. ### Question 1 1. **The FT of \( x(t)=2 \operatorname{sinc}(4 t) \)**: The Fourier Transform (FT) of the sinc function is a rectangular function. The FT of \( \operatorname{sinc}(at) \) is \( \frac{1}{|a|} \operatorname{rect}\left(\frac{f}{2a}\right) \). Here, \( a = 4 \), so: \[ \text{FT}\{2 \operatorname{sinc}(4t)\} = 2 \cdot \frac{1}{4} \operatorname{rect}\left(\frac{f}{8}\right) = \frac{1}{2} \operatorname{rect}\left(\frac{f}{8}\right) \] 2. **The FT of \( x(t)=2 \pi(2 t-2) \)**: This is a linear function. The FT of \( at + b \) is given by \( 2\pi j \delta'(f) + 2\pi b \delta(f) \). Here, \( a = 2\pi \) and \( b = -2\pi \): \[ \text{FT}\{2\pi(2t-2)\} = 2\pi j \delta'(f) - 4\pi^2 \delta(f) \] 3. **The FT of \( x(t)=2 \wedge\left(\frac{t-3}{2}\right) \)**: The triangular function has a known FT. The FT of \( \wedge(at) \) is \( \frac{1}{a^2} \operatorname{tri}\left(\frac{f}{a}\right) \). Here, \( a = \frac{1}{2} \): \[ \text{FT}\{2 \wedge\left(\frac{t-3}{2}\right)\} = 2 \cdot 2 \operatorname{tri}(2f) e^{-j 3f} = 4 \operatorname{tri}(2f) e^{-j 3f} \] 4. **The FT of \( x(t)=\pi\left(\frac{t}{2}\right) e^{-j 10 \pi t} \)**: The FT of \( x(t) e^{-j \omega_0 t} \) is \( X(f - \frac{\omega_0}{2\pi}) \). The FT of \( \pi\left(\frac{t}{2}\right) \) is \( 2 \operatorname{rect}(f) \): \[ \text{FT}\{\pi\left(\frac{t}{2}\right) e^{-j 10 \pi t}\} = 2 \operatorname{rect}(f + 5) \] ### Question 2 1. **The value of \( a_{1} \)**: The Fourier series coefficient \( a_n \) for \( x(t) = A \cos^2(\omega_0 t) \) can be calculated using the formula: \[ a_n = \frac{1}{T_0} \int_{0}^{T_0} x(t) e^{-j n \omega_0 t} dt \] Here, \( A = 4 \) and \( \omega_0 = 20\pi \). The average value of \( \cos^2 \) is \( \frac{1}{2} \), so: \[ a_0 = 2 \quad \text{and} \quad a_1 = 0 \] 2. **The dc-value of the signal \( x(t) \)**: The DC value is the average value over one period: \[ \text{DC value} = \frac{1}{T_0} \int_{0}^{T_0} x(t) dt \] The average value of \( 4 \cos^2(20 \pi t) \) is \( 2 \) and the average value of \( 2\sqrt{2} \sin(30 \pi t + \frac{\pi}{4}) \) is \( 0 \): \[ \text{DC value} = 2 \] 3. **The average power**: The average power \( P \) can be calculated as: \[ P = \frac{1}{T_0} \int_{0}^{T_0} |x(t)|^2 dt \] The average power of \( 4 \cos^2(20 \pi t) \) is \( 8 \) and for \( 2\sqrt{2} \sin(30 \pi t + \frac{\pi}{4}) \) is \( 2 \): \[ P = 8 + 2 = 10 \] 4. **The value of \( X_{-4} \)**: The Fourier series coefficient \( X_{-4} \) can be calculated similarly. Since \( \cos^2 \) and \( \sin \) functions do not contribute to negative frequencies, \( X_{-4} = 0 \). 5. **The fundamental frequency \( f_{O} \)**: The fundamental frequency is given by: \[ f_{O} = \frac{1}{T_0} \] The period \( T_0 \) is the least common multiple of the periods of the components: \[ T_0 = \frac{1}{20} \quad \text{and} \quad T_0 = \frac{1}{30} \quad \Rightarrow \quad f_{O} = \text{lcm}(20, 30) = 60 \text{ Hz} \] ### Summary of Answers 1. FT of \( x(t)=2 \operatorname{sinc}(4 t) \): \( \frac{1}{2} \operatorname{rect}\left(\frac{f}{8}\right) \) 2. FT of \( x(t)=2 \pi(2 t-2) \): \( 2\pi j \delta'(f) - 4\pi^2 \delta(f) \) 3. FT of \( x(t)=2 \wedge\left(\frac{t-3}{2}\right) \): \( 4 \operatorname{tri}(2f) e^{-j 3f} \) 4. FT of \( x(t)=\pi\left(\frac{t}{2}\right) e^{-j 10 \pi t} \): \( 2 \operatorname{rect}(f + 5) \) For Question 2: 1. \( a_{1} = 0 \) 2. DC value = 2

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The Fourier Transform (FT) is a fascinating mathematical tool that transforms signals from the time domain into the frequency domain. It helps us analyze the frequencies contained in a signal, revealing critical insights about its behavior. For instance, the sinc function, prevalent in signal processing, has a rectangular shape in the frequency domain, demonstrating how the FT creates a correspondence between time and frequency! Real-world applications of the Fourier Transform are everywhere! From audio signal processing, where it helps us manipulate sound waves for music production, to image compression techniques in JPEG files, FT enables efficient data handling. Even engineers use it to analyze vibrations in machinery. Understanding this transforms abstract math into a world of practical wonders!

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