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\( 1 \leftarrow \quad \) Multiply the following binomials. \[ (4 x-7 y)(7 x-y) \]

Ask by Lambert Lawson. in the United States
Mar 09,2025

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Answer

The product of the binomials \((4x - 7y)(7x - y)\) is \(28x^2 - 53xy + 7y^2\).

Solution

1. Expand the product using the distributive property (FOIL method): \[ (4x - 7y)(7x - y) = (4x)(7x) + (4x)(-y) + (-7y)(7x) + (-7y)(-y) \] 2. Multiply the terms: - First: \((4x)(7x) = 28x^2\) - Outer: \((4x)(-y) = -4xy\) - Inner: \((-7y)(7x) = -49xy\) - Last: \((-7y)(-y) = 7y^2\) 3. Combine like terms: \[ 28x^2 - 4xy - 49xy + 7y^2 = 28x^2 - 53xy + 7y^2 \] Thus, the product of the binomials is: \[ 28x^2 - 53xy + 7y^2 \]

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The Deep Dive

To multiply the binomials \( (4x - 7y)(7x - y) \), we can use the distributive property, also known as the FOIL method for binomials. First, multiply the first terms: \( 4x \cdot 7x = 28x^2 \). Next, multiply the outer terms: \( 4x \cdot (-y) = -4xy \). Then, the inner terms: \( -7y \cdot 7x = -49xy \). Lastly, the last terms: \( -7y \cdot (-y) = 7y^2 \). Combining all these gives us: \[ 28x^2 - 4xy - 49xy + 7y^2 = 28x^2 - 53xy + 7y^2. \] So the result is \( 28x^2 - 53xy + 7y^2 \). Alternatively, you could think of this as a way of combining like terms where you end up with a new polynomial that reflects the interaction between the two expressions! Mathematics is all about making connections, after all!

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