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Find the solution to the equation, \( 2 e^{3 y+8}-11 e^{5-10 y}=0 \) (correct to 4 decimal places) \( \} \mathrm{y}= \)

Ask by Luna Li. in Ghana
Mar 15,2025

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Tutor-Verified Answer

Answer

\( y \approx -0.0996 \)

Solution

Solve the equation \( 2e^(3y+8)-11e^(5-10y)=0 \). Solve the equation by following steps: - step0: Solve for \(y\): \(2e^{3y+8}-11e^{5-10y}=0\) - step1: Factor the expression: \(e^{5}\left(2e^{3}\times e^{13y}-11\right)\left(e^{y}\right)^{-10}=0\) - step2: Rewrite the expression: \(\frac{2e^{13y+8}-11e^{5}}{\left(e^{y}\right)^{10}}=0\) - step3: Cross multiply: \(2e^{13y+8}-11e^{5}=\left(e^{y}\right)^{10}\times 0\) - step4: Simplify the equation: \(2e^{13y+8}-11e^{5}=0\) - step5: Rewrite the expression: \(2e^{13y+8}=11e^{5}\) - step6: Divide both sides: \(\frac{2e^{13y+8}}{2}=\frac{11e^{5}}{2}\) - step7: Divide the numbers: \(e^{13y+8}=\frac{11e^{5}}{2}\) - step8: Take the logarithm of both sides: \(\ln{\left(e^{13y+8}\right)}=\ln{\left(\frac{11e^{5}}{2}\right)}\) - step9: Evaluate the logarithm: \(13y+8=\ln{\left(\frac{11e^{5}}{2}\right)}\) - step10: Move the constant to the right side: \(13y=\ln{\left(\frac{11e^{5}}{2}\right)}-8\) - step11: Divide both sides: \(\frac{13y}{13}=\frac{\ln{\left(\frac{11e^{5}}{2}\right)}-8}{13}\) - step12: Divide the numbers: \(y=\frac{\ln{\left(\frac{11e^{5}}{2}\right)}-8}{13}\) - step13: Simplify: \(y=\frac{\ln{\left(11\right)}-3-\ln{\left(2\right)}}{13}\) - step14: Simplify: \(y=\frac{\ln{\left(\frac{11}{2}\right)}-3}{13}\) - step15: Evaluate: \(y=\frac{\ln{\left(11\right)}-\ln{\left(2\right)}-3}{13}\) The solution to the equation \(2e^{3y+8}-11e^{5-10y}=0\) is \(y \approx -0.099635\) (correct to 4 decimal places).

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Beyond the Answer

To solve the equation \( 2 e^{3y+8} - 11 e^{5-10y} = 0 \), we can start by rearranging it: \[ 2 e^{3y+8} = 11 e^{5-10y}. \] Dividing both sides by \( e^{5-10y} \): \[ \frac{2 e^{3y+8}}{e^{5-10y}} = 11. \] This simplifies to: \[ 2 e^{3y + 8 + 10y - 5} = 11, \] \[ 2 e^{13y + 3} = 11. \] Now, isolate the exponential term: \[ e^{13y + 3} = \frac{11}{2}. \] Taking the natural logarithm of both sides gives: \[ 13y + 3 = \ln\left(\frac{11}{2}\right). \] Now, solve for \( y \): \[ 13y = \ln\left(\frac{11}{2}\right) - 3, \] \[ y = \frac{\ln\left(\frac{11}{2}\right) - 3}{13}. \] Calculating this yields: \[ y \approx \frac{\ln(5.5) - 3}{13} \approx \frac{1.7047 - 3}{13} \approx \frac{-1.2953}{13} \approx -0.0996. \] Thus, rounded to four decimal places, the solution is: \( y \approx -0.0996. \)

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