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1) \( f(x)=r x^{r}+r x \quad x=1 \)

Ask by Hodgson Young. in Iran
Jan 09,2025

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Answer

When \( x = 1 \), \( f(1) = 2r \).

Solution

To evaluate the function \( f(x) = r x^{r} + r x \) at \( x = 1 \), follow these steps: \[ f(1) = r \cdot (1)^{r} + r \cdot 1 \] Since any number raised to the power of 1 is itself: \[ f(1) = r \cdot 1 + r \cdot 1 = r + r = 2r \] **Answer:** When \( x = 1 \), \( f(1) = 2r \).

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The Deep Dive

Did you know that the function you’ve provided can showcase how quickly growth can explode when parameters are adjusted? When you evaluate \( f(1) \), you're essentially finding a mix of constants and a linear term, which gives a fascinating glimpse into polynomial behavior. You get \( f(1) = r \cdot 1^r + r \cdot 1 = 2r \). This means for every unit increase in \( r \), you're doubling it in your result. This kind of function has real-world applications in fields such as physics and economics, where you might model phenomena like population growth or profit strategies. By analyzing how \( r \) interacts with \( x \), you can predict how changes in input will affect outputs, making it a valuable tool for decision-making and forecasting in various industries!

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