Question
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(a) List all the divisors (factors) of 48 . (b) List all the divisors (factors) of 54 . (c) Use parts (a) and (b) to find the largest common divisor of 48 and 54 . (a) The divisors of 48 are \( \square \). (Simplify your answer. Use a comma to separate answers as needed.)

Ask by Davison Williams. in the United States
Mar 09,2025

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Tutor-Verified Answer

Answer

The divisors of 48 are 1, 2, 3, 4, 6, 8, 12, 16, 24, 48.

Solution

1. First, factorize 48 as \[ 48 = 2^4 \times 3. \] 2. To list all divisors of 48, consider all products of the factors where the exponent of 2 ranges from 0 to 4 and the exponent of 3 ranges from 0 to 1: - For the exponent of 2 equal to 0 and the exponent of 3 equal to 0: \(2^0 \times 3^0 = 1\). - For the exponent of 2 equal to 1 and the exponent of 3 equal to 0: \(2^1 \times 3^0 = 2\). - For the exponent of 2 equal to 0 and the exponent of 3 equal to 1: \(2^0 \times 3^1 = 3\). - For the exponent of 2 equal to 2 and the exponent of 3 equal to 0: \(2^2 \times 3^0 = 4\). - For the exponent of 2 equal to 1 and the exponent of 3 equal to 1: \(2^1 \times 3^1 = 6\). - For the exponent of 2 equal to 3 and the exponent of 3 equal to 0: \(2^3 \times 3^0 = 8\). - For the exponent of 2 equal to 2 and the exponent of 3 equal to 1: \(2^2 \times 3^1 = 12\). - For the exponent of 2 equal to 4 and the exponent of 3 equal to 0: \(2^4 \times 3^0 = 16\). - For the exponent of 2 equal to 3 and the exponent of 3 equal to 1: \(2^3 \times 3^1 = 24\). - For the exponent of 2 equal to 4 and the exponent of 3 equal to 1: \(2^4 \times 3^1 = 48\). 3. Hence, the divisors of 48 are \[ 1, 2, 3, 4, 6, 8, 12, 16, 24, 48. \]

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Extra Insights

The divisors of 48 are 1, 2, 3, 4, 6, 8, 12, 16, 24, 48. The divisors of 54 are 1, 2, 3, 6, 9, 18, 27, 54. The largest common divisor of 48 and 54 is 6.

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