13. Use Structure Peter bought $$ 4 imes\left(2 \frac{1}{4}+\frac{1}{2}+2 \frac{7}{8} ight) $$ yards of nbbon. Manilyn bought $$ 4 imes\left(2 \frac{1}{4}+\frac{1}{2}+3 ight) $$ yards of nibbon. Without doing any calculation determine who bought more ribbon

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13. Use Structure Peter bought $$ 4 	imes\left(2 \frac{1}{4}+\frac{1}{2}+2 \frac{7}{8}ight) $$ yards of nbbon. Manilyn bought $$ 4 	imes\left(2 \frac{1}{4}+\frac{1}{2}+3ight) $$ yards of nibbon. Without doing any calculation determine who bought more ribbon

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We need to compare the amounts of ribbon bought by Peter and Manilyn without performing calculations.

Peter's amount is given by:
$$ 
4 \times \left(2 \frac{1}{4} + \frac{1}{2} + 2 \frac{7}{8}\right) 
$$

Manilyn's amount is given by:
$$ 
4 \times \left(2 \frac{1}{4} + \frac{1}{2} + 3\right) 
$$

Both expressions have a common factor of $$4$$, so we can focus on the terms inside the parentheses for comparison.
Now, let's break down the terms inside the parentheses for both Peter and Manilyn:

- For Peter:
  - $$2 \frac{1}{4}$$ (which is $$2.25$$)
  - $$\frac{1}{2}$$ (which is $$0.5$$)
  - $$2 \frac{7}{8}$$ (which is $$2.875$$)

- For Manilyn:
  - $$2 \frac{1}{4}$$ (which is $$2.25$$)
  - $$\frac{1}{2}$$ (which is $$0.5$$)
  - $$3$$ (which is $$3.0$$)

Now, we can compare the sums of the terms inside the parentheses for both individuals.
For Peter, the sum of the terms is:
$$ 
2.25 + 0.5 + 2.875 = 5.625 
$$

For Manilyn, the sum of the terms is:
$$ 
2.25 + 0.5 + 3 = 5.75 
$$

Since $$5.75 > 5.625$$, Manilyn bought more ribbon than Peter.
Manilyn bought more ribbon than Peter.

Use Structure Peter bought
yards of nbbon.
Manilyn bought yards
of nibbon. Without doing any calculation
determine who bought more ribbon

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Use Structure Peter bought yards of nbbon. Manilyn bought yards of nibbon. Without doing any calculation determine who bought more ribbon