Factor \( 5 x^{2}-14 x+8 \)

To factor \( 5x^{2} - 14x + 8 \), we look for two numbers that multiply to \( 5 \times 8 = 40 \) and add up to \(-14\). The numbers \(-4\) and \(-10\) fit this requirement. Now we can rewrite the middle term: \[ 5x^{2} - 4x - 10x + 8 \] Next, we group the terms: \[ (5x^{2} - 4x) + (-10x + 8) \] Factoring out the common factors gives: \[ x(5x - 4) - 2(5x - 4) \] Now factor out \( (5x - 4) \): \[ (5x - 4)(x - 2) \] Thus, the factored form of \( 5x^{2} - 14x + 8 \) is: \[ (5x - 4)(x - 2) \]