Question
d \( \frac{15}{22} \div \frac{5}{33} \) h \( \frac{12}{5} \div \frac{3}{50} \)
Ask by Black Ortega. in Australia
Mar 12,2025
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Answer
**d.**
\[
\frac{15}{22} \div \frac{5}{33} = \frac{9}{2}
\]
**h.**
\[
\frac{12}{5} \div \frac{3}{50} = 40
\]
Solution
**d.**
1. Write the division as multiplication by the reciprocal:
\[
\frac{15}{22} \div \frac{5}{33} = \frac{15}{22} \times \frac{33}{5}
\]
2. Multiply the numerators and denominators:
\[
= \frac{15 \times 33}{22 \times 5} = \frac{495}{110}
\]
3. Simplify by dividing numerator and denominator by 5:
\[
= \frac{99}{22}
\]
4. Further simplify by dividing numerator and denominator by 11:
\[
= \frac{9}{2}
\]
**h.**
1. Write the division as multiplication by the reciprocal:
\[
\frac{12}{5} \div \frac{3}{50} = \frac{12}{5} \times \frac{50}{3}
\]
2. Multiply the numerators and denominators:
\[
= \frac{12 \times 50}{5 \times 3} = \frac{600}{15}
\]
3. Simplify the fraction:
\[
= 40
\]
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Simplify this solution Bonus Knowledge
To solve \( \frac{15}{22} \div \frac{5}{33} \), you can multiply by the reciprocal of the second fraction, which gives you \( \frac{15}{22} \times \frac{33}{5} \). Simplifying, you can reduce \(15\) and \(5\) to \(3\) and \(1\) respectively, and \(33\) and \(22\) to \(3\) and \(2\). This results in \( \frac{3 \times 3}{2 \times 1} = \frac{9}{2} \). For \( \frac{12}{5} \div \frac{3}{50} \), apply the same technique: multiply by the reciprocal, giving you \( \frac{12}{5} \times \frac{50}{3} \). Here, \(12\) and \(3\) reduce to \(4\) and \(1\), while \(50\) simplifies to \(10\) with \(5\). This results in \( \frac{4 \times 10}{1 \times 1} = \frac{40}{1} = 40 \).
