Elisa needs money to repair her home air conditioner, so she pawns her bicycle. The pawnbroker loans Elisa \( \$ 270 \). Ten days later, Elisa gets her bicycle back by paying the pawnbroker \( \$ 288.00 \). What annual simple interest rate did the \( 80.95 \%, 17 \) of 21 pawnbroker charge Elisa? Assume 360 days in a year. Tle pawnbroker charged Elisa a simple interest rate of (Round to the nearest whole number as needed.)
Upstudy AI Solution
Answer
Solution
Answered by UpStudy AI and reviewed by a Professional Tutor


Mind Expander
To find the annual simple interest rate charged by the pawnbroker, we can use the formula for simple interest: \[ I = P \times r \times t \] where \( I \) is the interest, \( P \) is the principal amount (the loan), \( r \) is the annual interest rate (as a decimal), and \( t \) is the time in years. 1. First, calculate the interest paid (I): \[ I = 288 - 270 = 18 \] 2. Next, we can express the loan duration in years: \[ t = \frac{10}{360} = \frac{1}{36} \] 3. Now plug the values into the simple interest formula: \[ 18 = 270 \times r \times \frac{1}{36} \] 4. Rearranging to find \( r \): \[ r = \frac{18 \times 36}{270} = \frac{648}{270} = 2.4 \] 5. To get the annual rate in percentage: \[ \text{Annual Interest Rate} = 2.4 \times 100 = 240 \] Therefore, the pawnbroker charged Elisa an annual simple interest rate of approximately **240%**.