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For a decagon (ten - sided polygon), find a. The number of diagonals drawn from one vertex. b. The number of triangles formed by the diagonal from one vertex. c. The sum of interior angles of the decagon. For the given figure,

Ask by Cummings Ellis. in Ethiopia
Mar 16,2025

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**a. Number of diagonals from one vertex:** 7 **b. Number of triangles formed by the diagonal from one vertex:** 8 **c. Sum of interior angles of the decagon:** 1440 degrees

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The Deep Dive

For a decagon, from one vertex, you can draw 7 diagonals. This is because you cannot connect to the two adjacent vertices and the vertex itself, leaving you with 10 - 3 = 7 diagonals. When you draw diagonals from one vertex in a decagon, you form 8 triangles. The vertex itself, along with two vertices connected by the diagonal, creates a triangle, and with 7 diagonals from one vertex, you will have 7 triangles plus the original triangle made by those two adjacent vertices. The sum of the interior angles of a decagon can be calculated using the formula (n - 2) × 180°, where n is the number of sides. For a decagon, that's (10 - 2) × 180° = 8 × 180° = 1440°. So, the sum of the interior angles is 1440°.

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