Given the following functions, find and simplify \( \left(\frac{f}{g}\right)(-3) \). \[ \begin{aligned} f(x)=x^{2}(3 x-2) \\ g(x)=3 x-2\end{aligned} \]
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To find \( \left(\frac{f}{g}\right)(-3) \), we first need to compute \( f(-3) \) and \( g(-3) \) using the given functions. Starting with \( f(x) = x^2(3x - 2) \): \[ f(-3) = (-3)^2(3(-3) - 2) = 9(-9 - 2) = 9(-11) = -99 \] Now for \( g(x) = 3x - 2 \): \[ g(-3) = 3(-3) - 2 = -9 - 2 = -11 \] Now we can calculate \( \left(\frac{f}{g}\right)(-3) \): \[ \left(\frac{f}{g}\right)(-3) = \frac{f(-3)}{g(-3)} = \frac{-99}{-11} = 9 \] Thus, the simplified value is: \[ \boxed{9} \]