What is the quotient? \( \frac{3 y+2}{3 y} \div \frac{6 y^{2}+4 y}{3 y+2} \)
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To find the quotient, we begin by rewriting the division of fractions as multiplication by the reciprocal. This gives us: \[ \frac{3y + 2}{3y} \div \frac{6y^2 + 4y}{3y + 2} = \frac{3y + 2}{3y} \times \frac{3y + 2}{6y^2 + 4y} \] Next, we can simplify \(6y^2 + 4y\): \[ 6y^2 + 4y = 2y(3y + 2) \] Substituting this back into our expression, we have: \[ \frac{3y + 2}{3y} \times \frac{3y + 2}{2y(3y + 2)} \] Notice that \(3y + 2\) in the numerator and denominator cancels out: \[ = \frac{3y + 2}{3y \cdot 2y} \] This simplifies further to: \[ = \frac{1}{6y} \] Thus, the final result is: \[ \frac{1}{6y} \]