Question
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Simplify the expression to \( a+b i \) form: \[ -\sqrt{9}+\sqrt{-98}-\sqrt{1}+\sqrt{-128} \]

Ask by Garza Wang. in the United States
Feb 28,2025

Upstudy AI Solution

Tutor-Verified Answer

Answer

The simplified expression is \( -4 + 15i\sqrt{2} \).

Solution

We start with the given expression:   -√9 + √(-98) - √1 + √(-128) Step 1: Simplify the real square roots.   √9 = 3  and √1 = 1 So the real parts become:   -3 - 1 = -4 Step 2: Simplify the square roots of negative numbers. Recall that √(-x) = i√x for x > 0.   √(-98) = i√98  and √(-128) = i√128 Factor the numbers under the square roots:   √98 = √(49×2) = 7√2   √128 = √(64×2) = 8√2 So the imaginary parts become:   √(-98) = 7i√2  and √(-128) = 8i√2 Step 3: Combine the imaginary parts.   7i√2 + 8i√2 = 15i√2 Step 4: Write the expression in a + bi form.   The simplified expression is:   -4 + 15i√2 Thus, the simplified expression in the form a + bi is:   -4 + 15i√2

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The Deep Dive

To simplify the expression \( -\sqrt{9}+\sqrt{-98}-\sqrt{1}+\sqrt{-128} \), let's break it down step-by-step. 1. Calculate each square root: - \( -\sqrt{9} = -3 \) - \( \sqrt{-98} = \sqrt{98}i = \sqrt{49 \cdot 2}i = 7\sqrt{2}i \) - \( -\sqrt{1} = -1 \) - \( \sqrt{-128} = \sqrt{128}i = \sqrt{64 \cdot 2}i = 8\sqrt{2}i \) 2. Combine all these results: \[ -3 + 7\sqrt{2}i - 1 + 8\sqrt{2}i \] 3. Combine the real parts and the imaginary parts: - Real part: \( -3 - 1 = -4 \) - Imaginary part: \( 7\sqrt{2}i + 8\sqrt{2}i = 15\sqrt{2}i \) Putting it all together, the expression simplifies to: \[ -4 + 15\sqrt{2}i \] So in \( a + bi \) form, the final answer is: \[ -4 + 15\sqrt{2}i \]

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