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f. Arrange in order from least to greatest: \( 1.3,1.35,1 . \overline{3} \)

Ask by Edwards Mann. in the United States
Mar 11,2025

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Answer

The order from least to greatest is \(1.3\), \(1.35\), and \(1.\overline{3}\).

Solution

To arrange the numbers \(1.3, 1.35, 1.\overline{3}\) in order from least to greatest, we need to compare their decimal representations. 1. \(1.3\) is a terminating decimal with two decimal places. 2. \(1.35\) is a terminating decimal with three decimal places. 3. \(1.\overline{3}\) is a repeating decimal where the digit 3 repeats infinitely. To compare these numbers, we can convert them to a common form. Let's convert \(1.\overline{3}\) to a decimal form by dividing it by 9: \[1.\overline{3} = \frac{1}{9} + \frac{3}{9} = \frac{4}{9} \approx 0.4444\] Now, we can compare the decimal representations: 1. \(1.3\) is less than \(1.35\). 2. \(1.35\) is less than \(1.\overline{3}\) (which is approximately 0.4444). Therefore, the order from least to greatest is: 1. \(1.3\) 2. \(1.35\) 3. \(1.\overline{3}\)

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To arrange the numbers \( 1.3, 1.35, \) and \( 1. \overline{3} \) from least to greatest, let's convert them into comparable forms. - \( 1.3 \) can be written as \( 1.30 \) - \( 1.35 \) remains the same. - \( 1. \overline{3} \) represents the repeating decimal \( 1.3333\ldots \) Now we compare: - \( 1.30 < 1.3333\ldots < 1.35 \) So, the order from least to greatest is \( 1.3, 1. \overline{3}, 1.35 \).

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