QUESTION 4 4.1 Arrange the following in descending order: \( -8 ;-1 ; 8 ;-16 ; 12 ;-12 ; 9 \) 4.2 Insert brackets to make the following true: \( 4.2 .1-4-3 \times-3-2=11 \) \( 4.2 .2 \quad 8 \div 2 \times 4+5-3 \times 2=0 \)
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To arrange the numbers in descending order, start with the largest value and work your way down. The order is: \( 12; 9; 8; -1; -8; -12; -16 \). Always keep in mind that negative numbers are smaller than positive ones! Now, for the equations, let's insert brackets. For \( 4.2.1\), you can rewrite it as \( 4 - (4 - 3) \times (-3) - 2 = 11 \). This adjusts the operations to get the desired result! For \( 4.2.2\), place brackets as follows: \( 8 \div (2 \times 4 + 5 - 3) \times 2 = 0\). It cleverly rearranges the operations to yield zero! Math can be quite the puzzle!