\( 2.1 .4 \sqrt { 25 } + \sqrt[ 3 ] { - 125 } + ( - 2 ) ^ { 2 } ( - 2 ) ^ { 3 } \)

We start with the expression \[ 2 \times 1.4 \times \sqrt{25} + \sqrt[3]{-125} + (-2)^2 \times (-2)^3. \] **Step 1. Evaluate \(\sqrt{25}\):** \[ \sqrt{25} = 5. \] The first term becomes \[ 2 \times 1.4 \times 5. \] **Step 2. Multiply the numbers in the first term:** \[ 2 \times 1.4 = 2.8, \] \[ 2.8 \times 5 = 14. \] So, the first term is \(14\). **Step 3. Evaluate the cube root \(\sqrt[3]{-125}\):** Since \[ (-5)^3 = -125, \] it follows that \[ \sqrt[3]{-125} = -5. \] **Step 4. Evaluate \((-2)^2 \times (-2)^3\):** Compute each part separately: \[ (-2)^2 = 4, \] \[ (-2)^3 = -8. \] Now multiply them: \[ 4 \times (-8) = -32. \] **Step 5. Sum all the evaluated parts:** \[ 14 + (-5) + (-32) = 14 - 5 - 32. \] First, \(14 - 5 = 9\), then \[ 9 - 32 = -23. \] The final answer is \[ -23. \]