6 Multiple Choice 1 point How would you describe the graph of $$ y=x^{2}+7 $$ ? Its vertex is at $$ (0,7) $$ and it opens upwark. Its vertex is at $$ (0,7) $$ and it opens to the right. Its vertex is at $$ (7,0) $$ and it opens to the left. Its vertex is at $$ (7,0) $$ and it opens downward.

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UpStudy AI · Accepted Answer

The graph of the equation $$ y = x^2 + 7 $$ is a parabola.

To analyze the equation:

1. The standard form of a parabola that opens upwards is $$ y = a(x - h)^2 + k $$, where $$ (h, k) $$ is the vertex.
2. In this case, the equation can be rewritten as $$ y = 1(x - 0)^2 + 7 $$, which shows that the vertex is at $$ (0, 7) $$.
3. Since the coefficient of $$ x^2 $$ is positive (1), the parabola opens upwards.

Based on this analysis, the correct description of the graph is:

**Its vertex is at $$ (0,7) $$ and it opens upward.**

However, this option is not listed in your choices. The closest option that matches the vertex is:

**Its vertex is at $$ (0,7) $$ and it opens upward.**

If you need to select from the provided options, none of them are correct.
The graph has a vertex at $$ (0,7) $$ and opens upward.

6 Multiple Choice 1 point How would you describe the graph of \( y=x^{2}+7 \) ? Its vertex is at \( (0,7) \) and it opens upwark. Its vertex is at \( (0,7) \) and it opens to the right. Its vertex is at \( (7,0) \) and it opens to the left. Its vertex is at \( (7,0) \) and it opens downward.

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