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Multiply. \( (b-4)(2 b+6) \)

Ask by Goodwin Wells. in the United States
Mar 09,2025

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Answer

\( 2b^2 - 2b - 24 \)

Solution

1. Expand using the distributive property: \[ (b-4)(2b+6) = b(2b+6) - 4(2b+6) \] 2. Multiply each term: \[ b(2b+6) = 2b^2 + 6b \] \[ -4(2b+6) = -8b - 24 \] 3. Combine like terms: \[ 2b^2 + 6b - 8b - 24 = 2b^2 - 2b - 24 \] The final result is: \[ 2b^2 - 2b - 24 \]

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To multiply the expression \( (b-4)(2b+6) \), you can use the distributive property, often known as the FOIL method for binomials. Multiply each term in the first binomial by each term in the second binomial: 1. First: \( b \cdot 2b = 2b^2 \) 2. Outside: \( b \cdot 6 = 6b \) 3. Inside: \( -4 \cdot 2b = -8b \) 4. Last: \( -4 \cdot 6 = -24 \) Now, combine these results: \[ 2b^2 + 6b - 8b - 24 = 2b^2 - 2b - 24 \] Thus, the expanded expression is \( 2b^2 - 2b - 24 \).

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