Thare \( q \) the subject of prormular in: \[ t=\sqrt{\frac{p q}{r}-r^{2} q} \]

To make \( q \) the subject of the formula in the equation \[ t = \sqrt{\frac{pq}{r} - r^2 q}, \] we will first eliminate the square root by squaring both sides: \[ t^2 = \frac{pq}{r} - r^2 q. \] Next, we can rearrange the equation to isolate the terms involving \( q \): \[ t^2 + r^2 q = \frac{pq}{r}. \] Now, we can express \( q \) in terms of \( t^2 \) and \( p \). First, let's multiply both sides by \( r \) to eliminate the fraction: \[ r t^2 + r^3 q = pq. \] Now, we can rearrange this to isolate \( q \): \[ r^3 q = pq - r t^2. \] Next, we can solve for \( q \) by dividing both sides by \( r^3 \): \[ q = \frac{pq - r t^2}{r^3}. \] Thus, the expression for \( q \) in terms of \( p \), \( r \), and \( t \) is: \[ \boxed{q = \frac{pq - r t^2}{r^3}}. \]