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ION 4 - 1 POINT the function \( h(x) \) below, select the answer choice which correctly decomposes \( h(x) \) into component functions \( f \) ( \( (x) \) so that \( h(x) \Rightarrow f(g(x)) \). \[ h(x)=(-x+6)^{2} \] the correct answer below: \( (x)=f(g(x)) \), where \( f(x)=-x \) and \( g(x)=(x+6)^{2} \) \( (x)=f(g(x)) \), where \( f(x)=-x+6 \) and \( g(x)=x^{2} \)

Ask by Willis Pierce. in the United States
Mar 01,2025

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Tutor-Verified Answer

Answer

The correct decomposition is \( f(x) = x^2 \) and \( g(x) = -x + 6 \), so \( h(x) = f(g(x)) = (-x + 6)^2 \). Neither of the provided answer choices is correct.

Solution

To decompose the function \( h(x) = (-x + 6)^2 \) into component functions \( f \) and \( g \) such that \( h(x) = f(g(x)) \), we need to identify suitable functions \( f \) and \( g \). 1. **Identify the structure of \( h(x) \)**: - The function \( h(x) \) is a composition of two operations: first, we apply the linear transformation \( -x + 6 \), and then we square the result. 2. **Choose \( g(x) \)**: - A natural choice for \( g(x) \) is the inner function that we apply first. In this case, we can let: \[ g(x) = -x + 6 \] 3. **Choose \( f(x) \)**: - The outer function \( f(x) \) will then be the operation we apply to \( g(x) \). Since we are squaring the result of \( g(x) \), we can define: \[ f(x) = x^2 \] 4. **Combine \( f \) and \( g \)**: - Now we can express \( h(x) \) as: \[ h(x) = f(g(x)) = f(-x + 6) = (-x + 6)^2 \] Now, let's check the provided answer choices: 1. **First choice**: \( f(x) = -x \) and \( g(x) = (x + 6)^2 \) - This does not match our decomposition since \( g(x) \) should not be squared. 2. **Second choice**: \( f(x) = -x + 6 \) and \( g(x) = x^2 \) - This also does not match our decomposition since \( g(x) \) should not be \( x^2 \). Neither of the provided answer choices correctly decomposes \( h(x) \) into \( f(g(x)) \). The correct decomposition is: - \( g(x) = -x + 6 \) - \( f(x) = x^2 \) Thus, the correct answer is not listed among the choices provided.

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Bonus Knowledge

To break down \( h(x) = (-x + 6)^2 \) into component functions \( f \) and \( g \), we can start by looking at the structure of the equation. The outer function \( f \) should operate on the output of the inner function \( g \). Here, we find that \( g(x) = -x + 6 \) will yield the expression that needs squaring, making \( f(x) = x^2 \). Thus, \( h(x) = f(g(x)) \) becomes \( h(x) = f(-x + 6) = (-x + 6)^2 \). One common mistake in function decomposition is misidentifying which operation is at the outer layer and which is at the inner layer. Always remember to identify the last operation you perform as the outer function, and everything inside it as part of the inner function. By correctly recognizing the hierarchy of operations, you'll easily avoid these pitfalls!

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