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Find \( \frac{d s}{d t} \) if \( s=\frac{t}{7 t+3} \) \( \frac{d s}{d t}=\square \)

Ask by Henry Mckenzie. in the United States
Mar 09,2025

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Answer

\[ \frac{ds}{dt} = \frac{3}{(7t+3)^2} \]

Solution

We are given \[ s = \frac{t}{7t+3}. \] To find \(\frac{ds}{dt}\), we use the quotient rule. The quotient rule states that if \[ s = \frac{u(t)}{v(t)}, \] then \[ \frac{ds}{dt} = \frac{v(t) \cdot \frac{d}{dt}[u(t)] - u(t) \cdot \frac{d}{dt}[v(t)]}{[v(t)]^2}. \] Let \[ u(t) = t \quad \text{and} \quad v(t) = 7t+3. \] First, compute the derivatives: \[ \frac{d}{dt}[u(t)] = 1 \quad \text{and} \quad \frac{d}{dt}[v(t)] = 7. \] Now substitute into the quotient rule formula: \[ \frac{ds}{dt} = \frac{(7t+3)(1) - t(7)}{(7t+3)^2}. \] Simplify the numerator: \[ (7t+3) - 7t = 3. \] Thus, we have: \[ \frac{ds}{dt} = \frac{3}{(7t+3)^2}. \] So, the derivative is: \[ \frac{ds}{dt} = \boxed{\frac{3}{(7t+3)^2}}. \]

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To find \( \frac{d s}{d t} \) for the function \( s = \frac{t}{7t + 3} \), we can use the quotient rule of differentiation. The quotient rule states that if you have a function \( s = \frac{u}{v} \), then the derivative is given by: \[ \frac{d s}{d t} = \frac{u'v - uv'}{v^2} \] Here, \( u = t \) and \( v = 7t + 3 \). Calculating \( u' \) and \( v' \): - \( u' = 1 \) - \( v' = 7 \) Now, we can apply the quotient rule: \[ \frac{d s}{d t} = \frac{(1)(7t + 3) - (t)(7)}{(7t + 3)^2} \] Simplifying the numerator: \[ 7t + 3 - 7t = 3 \] Thus: \[ \frac{d s}{d t} = \frac{3}{(7t + 3)^2} \] So, the final result is: \[ \frac{d s}{d t} = \frac{3}{(7t + 3)^2} \]

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