Find \( \frac{d s}{d t} \) if \( s=\frac{t}{7 t+3} \) \( \frac{d s}{d t}=\square \)
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To find \( \frac{d s}{d t} \) for the function \( s = \frac{t}{7t + 3} \), we can use the quotient rule of differentiation. The quotient rule states that if you have a function \( s = \frac{u}{v} \), then the derivative is given by: \[ \frac{d s}{d t} = \frac{u'v - uv'}{v^2} \] Here, \( u = t \) and \( v = 7t + 3 \). Calculating \( u' \) and \( v' \): - \( u' = 1 \) - \( v' = 7 \) Now, we can apply the quotient rule: \[ \frac{d s}{d t} = \frac{(1)(7t + 3) - (t)(7)}{(7t + 3)^2} \] Simplifying the numerator: \[ 7t + 3 - 7t = 3 \] Thus: \[ \frac{d s}{d t} = \frac{3}{(7t + 3)^2} \] So, the final result is: \[ \frac{d s}{d t} = \frac{3}{(7t + 3)^2} \]