\( \begin{array}{r}10 \text { yd } 22 \text { in. } \\ +\quad 9 \text { yd } 19 \text { in. } \\ \hline\end{array} \)

1. Write the two amounts: - \(10 \text{ yd } 22 \text{ in.}\) - \(9 \text{ yd } 19 \text{ in.}\) 2. Add the yards: \[ 10 \text{ yd } + 9 \text{ yd } = 19 \text{ yd } \] 3. Add the inches: \[ 22 \text{ in. } + 19 \text{ in. } = 41 \text{ in. } \] 4. Convert the inches into yards and inches: - Since \(1 \text{ yd } = 36 \text{ in.}\), divide \(41\) by \(36\): \[ 41 \div 36 = 1 \text{ yd } \text{ remainder } 5 \text{ in.} \] 5. Combine the converted yards with the previously obtained yards: \[ 19 \text{ yd } + 1 \text{ yd } = 20 \text{ yd } \] and we have \(5 \text{ in.}\) remaining. The final answer is: \[ 20 \text{ yd } 5 \text{ in.} \]