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\( 1 \leftarrow \quad \begin{array}{l}\text { Subtract and simplify } \\ (14+6 i)-(9+3 i)\end{array} \)

Ask by Matthews Cox. in the United States
Feb 28,2025

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Answer

The simplified result is 5 + 3i.

Solution

To subtract and simplify (14 + 6i) - (9 + 3i), subtract the real parts and the imaginary parts separately: Real parts: 14 - 9 = 5 Imaginary parts: 6i - 3i = 3i So, the simplified result is 5 + 3i.

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Bonus Knowledge

To subtract and simplify the complex numbers \( (14 + 6i) - (9 + 3i) \), you simply subtract the real parts and the imaginary parts separately. So, for the real parts: \( 14 - 9 = 5 \) and for the imaginary parts: \( 6i - 3i = 3i \). Putting it all together, you get \( 5 + 3i \). Now you have your simplified result: \( 1 \leftarrow 5 + 3i \)! If you're feeling a little unsure about complex numbers, remember that visualizing them on the complex plane can be super helpful. The x-axis represents the real part while the y-axis represents the imaginary part. Plotting these numbers can give you a clearer understanding of their relationship and operations! Don't forget that a common mistake is forgetting to distribute negative signs correctly when subtracting. Double-check your signs to avoid errors. For instance, \( (14 + 6i) - (9 + 3i) \) might be mistakenly simplified as \( 14 + 6i - 9 - 3i \) without careful attention to the negative sign in front of the second complex number!

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