Find all real solutions of the equation by completing the square \( x^{2}-10 x+20=4 \). \( x_{1}=\square \) with \( x_{1} \) Next Question

To solve the equation \( x^{2}-10x+20=4 \) by completing the square, we first rearrange the equation: \( x^{2}-10x+16=0 \). Now, to complete the square, we can rewrite the quadratic expression. First, take half of the coefficient of \( x \) (which is -10), square it, and add it inside the completed square: \[ x^{2}-10x+25-25+16=0 \implies (x-5)^{2}=9. \] Taking the square root of both sides gives us: \[ x - 5 = 3 \quad \text{or} \quad x - 5 = -3. \] This simplifies to: \[ x = 8 \quad \text{or} \quad x = 2. \] Thus, the solutions are \( x_{1} = 2 \) and \( x_{2} = 8 \). So, we have \( x_{1}=2 \) with \( x_{1} Next Question