Simplify $$ 8^{-5} imes 8^{3} $$. A $$ \frac{1}{8^{8}} $$ B $$ \frac{1}{8^{2}} $$ C $$ -8^{-15} $$ D $$ 8^{-15} $$

Question

Simplify $$ 8^{-5} 	imes 8^{3} $$. A $$ \frac{1}{8^{8}} $$ B $$ \frac{1}{8^{2}} $$ C $$ -8^{-15} $$ D $$ 8^{-15} $$

UpStudy AI · Accepted Answer

We start with the expression:

$$
8^{-5} \times 8^{3}
$$

Using the law of exponents, we add the exponents when multiplying like bases:

$$
8^{-5} \times 8^{3} = 8^{-5+3} = 8^{-2}
$$

The term $$8^{-2}$$ can be rewritten as:

$$
8^{-2} = \frac{1}{8^2}
$$

Thus, the simplified expression is $$\frac{1}{8^2}$$, which corresponds to option B.
The simplified expression is $$ \frac{1}{8^{2}} $$, which is option B.

Simplify \( 8^{-5} \times 8^{3} \). A \( \frac{1}{8^{8}} \) B \( \frac{1}{8^{2}} \) C \( -8^{-15} \) D \( 8^{-15} \)

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