From the 7 male and 7 female sales representatives for an insurance company, a team of 2 men and 4 women will be selected to attend a national conference on insurance fraud. In how many ways can the team of 6 be selected?

To form a team of 2 men and 4 women, we can use combinations. First, we choose 2 men from the 7 available: \[ \binom{7}{2} = \frac{7!}{2!(7-2)!} = \frac{7 \times 6}{2 \times 1} = 21. \] Next, we choose 4 women from the 7 available: \[ \binom{7}{4} = \binom{7}{3} = \frac{7!}{4!(7-4)!} = \frac{7 \times 6 \times 5}{3 \times 2 \times 1} = 35. \] Now, we multiply the two results together to find the total number of ways to select the team: \[ 21 \times 35 = 735. \] Thus, the team of 6 can be selected in 735 different ways.