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Write out the sample space and assume each outcome is equally likely. Then give the probability of the requested outcomes. A man is shopping for a new patio umbrella. There is a 10-foot and a 14 -foot model, and each is available in black, sky blue, and rust. (a) He buys a 14 -foot sky blue umbrella. (b) He buys a 10-foot umbrella. (c) He buys a black-colored umbrella. (b) He buys a 10-foot umbrella. The probability is \( \square \). (Type an integer or a simplified fraction.)

Ask by Erickson Harper. in the United States
Mar 03,2025

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Answer

- **(a)** The probability of buying a 14-foot sky blue umbrella is \( \frac{1}{6} \). - **(b)** The probability of buying a 10-foot umbrella is \( \frac{1}{2} \). - **(c)** The probability of buying a black-colored umbrella is \( \frac{1}{3} \).

Solution

We first list out the sample space. There are two sizes (10‑foot and 14‑foot) and three colors (black, sky blue, and rust). We can list each outcome as an ordered pair (size, color). The sample space S is:  S = { (10, black), (10, sky blue), (10, rust), (14, black), (14, sky blue), (14, rust) } Since each outcome is equally likely, the total number of outcomes is 6. Now we answer each part: (a) "He buys a 14‑foot sky blue umbrella."  There is exactly 1 outcome that meets this: (14, sky blue).  Probability = 1/6. (b) "He buys a 10‑foot umbrella."  The outcomes with a 10‑foot umbrella are: (10, black), (10, sky blue), and (10, rust).  That totals 3 outcomes.  Probability = 3/6 = 1/2. (c) "He buys a black-colored umbrella."  The outcomes with a black umbrella are: (10, black) and (14, black).  That totals 2 outcomes.  Probability = 2/6 = 1/3. Thus, the answers are: (a) 1/6 (b) 1/2 (c) 1/3

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The Deep Dive

First, let's outline the sample space. The man has two models of patio umbrellas (10-foot and 14-foot) and three colors (black, sky blue, rust). Therefore, the complete sample space consists of the following outcomes: 1. 10-foot black 2. 10-foot sky blue 3. 10-foot rust 4. 14-foot black 5. 14-foot sky blue 6. 14-foot rust This results in a total of 6 equally likely outcomes. Now, we can find the probabilities for each requested outcome: (a) The outcome "buys a 14-foot sky blue umbrella" corresponds to 1 favorable outcome out of 6 total outcomes. Thus, the probability is \( \frac{1}{6} \). (b) The outcome "buys a 10-foot umbrella" corresponds to 3 favorable outcomes (10-foot black, sky blue, rust) out of 6 total outcomes. So, the probability is \( \frac{3}{6} = \frac{1}{2} \). (c) The outcome "buys a black-colored umbrella," which can be either 10-foot black or 14-foot black, corresponds to 2 favorable outcomes out of 6. Therefore, the probability is \( \frac{2}{6} = \frac{1}{3} \). The probability for the repeated request (b) remains \( \frac{1}{2} \) as calculated above.

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