a. \( 2 \frac{2}{3}+1 \frac{1}{2}+3 \frac{3}{4}= \)

To tackle this problem, let’s convert these mixed numbers into improper fractions. For \(2 \frac{2}{3}\), you get \(\frac{8}{3}\); for \(1 \frac{1}{2}\), you have \(\frac{3}{2}\); and for \(3 \frac{3}{4}\), it becomes \(\frac{15}{4}\). Finding a common denominator (which is 12 in this case) makes it simple: - \(\frac{8}{3} = \frac{32}{12}\) - \(\frac{3}{2} = \frac{18}{12}\) - \(\frac{15}{4} = \frac{45}{12}\) Now, add these together: \(\frac{32}{12} + \frac{18}{12} + \frac{45}{12} = \frac{95}{12}\). This equals \(7 \frac{11}{12}\) when converted back to a mixed number! Let’s toast to math magic! 🎉