Suppose that the functions $$ h $$ and $$ g $$ are defined as follows. $$ h(x)=5-3 x^{2} $$ $$ g(x)=4-6 x $$ (a) Find $$ \left(\frac{h}{g}\right)(4) $$. (b) Find all values that are NOT in the domain of $$ \frac{h}{g} $$. If there is more than one value, separate them with commas. (a) $$ \left(\frac{h}{g}\right) $$ (4) = m (b) Value(s) that are NOT in the domain of $$ \frac{h}{g}: \square $$

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**Step 1.** Write down the functions:  
$$
h(x)=5-3x^2,\quad g(x)=4-6x.
$$

**Step 2.** Evaluate $$ h(4) $$ and $$ g(4) $$:  
$$
h(4)=5-3(4)^2=5-3(16)=5-48=-43,
$$
$$
g(4)=4-6(4)=4-24=-20.
$$

**Step 3.** Compute $$\left(\frac{h}{g}\right)(4)$$:  
$$
\left(\frac{h}{g}\right)(4)=\frac{h(4)}{g(4)}=\frac{-43}{-20}=\frac{43}{20}.
$$

**Step 4.** Determine the domain of $$\frac{h}{g}$$:  
The function is undefined when $$ g(x)=0 $$. Solve for $$ x $$:
$$
4-6x=0 \quad \Longrightarrow \quad -6x=-4 \quad \Longrightarrow \quad x=\frac{2}{3}.
$$
Thus, $$ x=\frac{2}{3} $$ is not in the domain.

**Final Answers:**  
(a) $$ \left(\frac{h}{g}\right)(4)=\frac{43}{20} $$

(b) The value that is NOT in the domain of $$\frac{h}{g}$$ is $$ \frac{2}{3} $$.
(a) $$ \left(\frac{h}{g}\right)(4) = \frac{43}{20} $$ (b) $$ \frac{2}{3} $$

Suppose that the functions and are defined as follows.

(a) Find .
(b) Find all values that are NOT in the domain of .
If there is more than one value, separate them with commas.
(a) (4) = m
(b) Value(s) that are NOT in the domain of

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Suppose that the functions and are defined as follows. (a) Find . (b) Find all values that are NOT in the domain of . If there is more than one value, separate them with commas. (a) (4) = m (b) Value(s) that are NOT in the domain of