Question
A player is dealt 4 cards from a standard 52 -card deck. Determine the probability of being dealt three of a kind (such as three aces or three kings) by answering questions a through d.
a) How many ways can 4 cards be selected from a 52 -card deck?
There are 270,725 ways that 4 cards can be selected from a 52 -card deck.
(Type a whole number.)
b) Each deck contains 4 twos, 4 threes, and so on. How many ways can three of the same card be selected from the deck?
There are 52 ways that three of the same card can be selected from the deck.
(Type a whole number.)
c) The remaining card must be different from the 3 chosen. After selecting the three of a kind, there are 12 different ranks of cards remaining in the deck that can be chosen. Of the 12 ranks remaining, the
player chooses 1 of them and then selects one of the 4 cards in the chosen rank. How many ways can the player select the remaining card?
There are 48 ways the player can select the remaining card.
(Type a whole number.)
d) Use the General Multiplication Rule to compute the probability of obtaining three of a kind. That is, what is the probability of selecting three of a kind and one card that is different?
The probability of obtaining three of a kind from 4 cards dealt is
(Round to four decimal places as needed.)
A player is dealt 4 cards from a standard 52 -card deck. Determine the probability of being dealt three of a kind (such as three aces or three kings) by answering questions a through d.
a) How many ways can 4 cards be selected from a 52 -card deck?
There are 270,725 ways that 4 cards can be selected from a 52 -card deck.
(Type a whole number.)
b) Each deck contains 4 twos, 4 threes, and so on. How many ways can three of the same card be selected from the deck?
There are 52 ways that three of the same card can be selected from the deck.
(Type a whole number.)
c) The remaining card must be different from the 3 chosen. After selecting the three of a kind, there are 12 different ranks of cards remaining in the deck that can be chosen. Of the 12 ranks remaining, the
player chooses 1 of them and then selects one of the 4 cards in the chosen rank. How many ways can the player select the remaining card?
There are 48 ways the player can select the remaining card.
(Type a whole number.)
d) Use the General Multiplication Rule to compute the probability of obtaining three of a kind. That is, what is the probability of selecting three of a kind and one card that is different?
The probability of obtaining three of a kind from 4 cards dealt is
(Round to four decimal places as needed.)
Ask by Schultz Carter. in the United States
Mar 25,2025
Upstudy AI Solution
Tutor-Verified Answer
Answer
The probability of being dealt three of a kind is approximately 0.0092.
Solution

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The Deep Dive
To find the probability of being dealt three of a kind when 4 cards are drawn from a 52-card deck, we can follow these steps:
First, we will calculate the total number of ways to get three of a kind and one different card. As given:
- There are 52 ways to choose which rank will have three of a kind.
- After choosing the rank for three of a kind, there are 48 combinations for choosing the remaining card.
Thus, the total ways to form three of a kind along with one different card is:
Now, we know from part (a) that there are 270,725 ways to select any 4 cards from the deck.
Finally, we calculate the probability by dividing the number of favorable outcomes by the total outcomes:
So, rounding to four decimal places, the probability of being dealt three of a kind is 0.0092.