Write a recursive formula for the sequence \( 7,13,19,25,31, \ldots \) Then find the next term. \( \begin{array}{l}\text { a. } a_{n}=a_{n-1}+6 \text {, where } a_{1}=7 ; 37 \\ \text { b. } a_{n}=a_{n-1}+6 \text {, where } a_{1}=37 ; 7 \\ \text { c. } a_{n}=a_{n-1}-6 \text {, where } a_{1}=7 ; 37 \\ \text { d. } a_{n}=a_{n-1}-6 \text {, where } a_{1}=6 ;-23\end{array} \)

The sequence provided is an arithmetic sequence, where each term increases by 6. This establishes that the recursive formula should indeed be \( a_{n} = a_{n-1} + 6 \), starting from \( a_{1} = 7 \). To find the next term following \( 31 \), we calculate \( 31 + 6 = 37 \). So, the answer is \( a. \) \( a_{n}=a_{n-1}+6 \text{, where } a_{1}=7 ; 37 \). Keep up the math momentum! Understanding recursive formulas in sequences like this can help with more complex problems down the line. It’s the key to unveiling patterns, and guess what? Patterns are everywhere!