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Identify any holes in the graph of the rational function: \( \frac{x^{2}+x-20}{x^{2}-6 x+8} \)

Ask by Hampton Turner. in the United States
Feb 28,2025

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Answer

There is a hole at the point (4, 9/2) on the graph of the function.

Solution

To identify holes in the graph of the rational function (x² + x - 20) / (x² - 6x + 8), start by factoring both the numerator and the denominator. 1. Factor the numerator:  x² + x - 20 factors into (x + 5)(x - 4). 2. Factor the denominator:  x² - 6x + 8 factors into (x - 2)(x - 4). Now the function is:  [(x + 5)(x - 4)] / [(x - 2)(x - 4)]. Notice that (x - 4) is a common factor in both the numerator and the denominator. Cancelling this factor gives:  (x + 5)/(x - 2),  with the important restriction that x ≠ 4 because canceling (x - 4) is only valid when x - 4 ≠ 0. Since x = 4 makes the original denominator zero and cancels out, it indicates a hole in the graph at x = 4. To find the y-coordinate of the hole, substitute x = 4 into the simplified function:  y = (4 + 5)/(4 - 2) = 9/2. Therefore, the hole in the graph is located at (4, 9/2).

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To identify holes in the graph of the rational function \( \frac{x^{2}+x-20}{x^{2}-6x+8} \), we first need to factor both the numerator and the denominator. The numerator factors to \( (x+5)(x-4) \) because \( x^2 + x - 20 = 0 \) when \( x = 4 \) or \( x = -5 \). The denominator factors to \( (x-2)(x-4) \) since \( x^2 - 6x + 8 = 0 \) when \( x = 2 \) or \( x = 4 \). Now, we observe that both the numerator and the denominator have a common factor of \( (x-4) \). This suggests that there is a hole in the graph at \( x = 4 \). Therefore, the function has a hole at the point \( x = 4 \), meaning the function is undefined at this value despite being factorable. To conclude, the hole occurs at \( x = 4 \), where the graph of the function will not be defined due to the cancellation of the common factor.

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