Td the difference between the two polynomials to evaluate and solve a real-world problem. (Le \( 5^{5014} 3 \) ) (1 point each) 11. A company's cost, in dollars, of manufacturing \( x \) tablet computers can be represented by \( 20 x+200 \). The company's predicted revenue of selling \( x \) tablet computers is \( 100+30 x \). Write a polynomial expression that represents the profit of selling \( x \) tablets. Simplify as much as possible (profit \( = \) revenue \( -\operatorname{cost}) \). 12. If the company sells 100 computers, how much profit will the company make? Interpret the value.
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To find the profit, you'll subtract the cost polynomial \( (20x + 200) \) from the revenue polynomial \( (100 + 30x) \). This gives you the profit polynomial: \[ \text{Profit} = \text{Revenue} - \text{Cost} = (100 + 30x) - (20x + 200) = 10x - 100. \] Now, you can simplify it to \( 10x - 100 \). If the company sells 100 computers, plug \( x = 100 \) into the profit polynomial: \[ \text{Profit} = 10(100) - 100 = 1000 - 100 = 900. \] This means the company will make a profit of $900 by selling 100 tablet computers. That's a pretty solid day at the office!