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126 III LEY DE OHM, POTENCIA Y ENERGIA 23. ¿Cuánto tiempo debe existir una corriente permanente de 2 A en un resistor que tiene 3 V en él para disipar 12 J de energía? 39.

Ask by Mullins Johnson. in Mexico
Mar 19,2025

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El tiempo necesario es 2 segundos.

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Para calcular el tiempo durante el cual debe existir una corriente de 2 A en un resistor con una caída de tensión de 3 V para disipar 12 J de energía, se puede utilizar la fórmula de energía: \( E = P \times t \). Primero, calculamos la potencia (P) usando la Ley de Ohm: \( P = V \times I = 3 \, V \times 2 \, A = 6 \, W \). Luego, sustituimos en la fórmula de energía: \( 12 \, J = 6 \, W \times t \), lo que da \( t = 12 \, J / 6 \, W = 2 \, s \). Por lo tanto, la corriente debe fluir durante 2 segundos. ¿Sabías que la Ley de Ohm, formulada por el físico alemán Georg Simon Ohm en 1827, revolucionó la comprensión de la electricidad? Este principio básico establece que la corriente es directamente proporcional a la tensión e inversamente proporcional a la resistencia. Desde entonces, ha sido fundamental en diversas aplicaciones eléctricas, desde circuitos domésticos hasta la complejidad de los dispositivos electrónicos modernos. En el camino hacia la resolución de problemas eléctricos, un error común es no considerar que la potencia y la energía son conceptos diferentes. La potencia se refiere a la tasa de consumo de energía, mientras que la energía es la cantidad total consumida a lo largo del tiempo. ¡Recuerda siempre distinguir entre estos dos para evitar confusiones en tus cálculos!

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Physics Philippines Mar 19, 2025
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